国产人妻人伦精品_欧美一区二区三区图_亚洲欧洲久久_日韩美女av在线免费观看

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

CSCC43代做、R設計編程代寫

時間:2023-11-27  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



CSCC43 – Fall 2023 University of Toronto Scarborough
Intro to Databases – Assignment #3
Nov18, 2023
This assignment may be completed in a max group of 2 .
Please provide detailed answers to the following exercises.
Read the note on academic Integrity.
Instructions:
There are two parts in this assignment.
• Part 1 (3 questions – 40 points)
o Requires you to design ER Diagram given specification using any online drawing tool.
o Requires conversion from ER diagrams to relational schemas and improved version of
ER diagrams.
o Requires you to design an ER diagram given a relational schema.
o Note: Handwritten solutions/diagrams will not be accepted.
• Part 2 (6 questions with subparts - 60 points)
o Requires you to answer questions on functional dependencies and normal forms.
Submission: Quercus
For this assignment, you need to submit all typed solutions in a single PDF named
Assignment3.pdf. You can use LaTeX or any other word processing software. ER Diagrams should
be computer generated as well and should not be hand drawn.
Note: Late submissions with 10% penalty will be accepted until up to December 4th 11:59 pm.
No submissions will be accepted after that.
Assignment #3
Total: 100 points
Due Date: Dec 2nd, 2023 11:59pm
CSCC43 – Fall 2023 University of Toronto Scarborough
Part 1: Entity Relationship Model [40 marks]
Question 1 [25 marks]
For this question, you will design Entity Relationship Diagram and a database schema for
an Ice Hockey Tournament.
System Functional Requirements:
The administrator of tournament website and the database is the primary user who manages
the data associated with the tournament that includes information about players, teams,
coaches, matches, referees, etc.
The administrator wants following features included in your design and describes these
features as follows:
For each match, we store the series and the tournament day on which it takes place, which
match it is, (e.g., first match, second match, etc.) the date with day, month, year, the teams
involved in the match with the name of the city and the coach, and finally for each team
whether that team played at home. Each team can have multiple coaches and for each coach,
we record their name, salary, and city of birth.
We store the name and the surname of each player in each team with his date of birth and
main position. We store, for each day, how many points each team has, and we also store
for each match, the player of each team who played and in which position each player played
(the position can change from one game to another). For each match, we store the referee,
with first name, surname, city, and region of birth.
The match played as scheduled must be distinguished from those postponed. For a
postponed match, we store the date in which it is actually played. We also identify the
matches played in a city other than that of the home team; for each of these, we store the
city in which it took place, as well as the reason for the variation venue. For each player, we
are interested in the city of birth.
We also record the contracts between players and teams including the past contracts with
the date of beginning and end of the contracts for each player in each team. It is possible that
a player can have different contracts with the same team in different periods. For all contracts
we wish to know the date of commencement. Similarly, we also record contracts between
coach and teams.
Question 1.1 [15 marks]:
Design and draw an ER schema that captures the information given above. Your schema
should model explicitly entities and relationships in the domain of Ice Hockey Tournament,
also their attributes, generalization relationships, keys, and cardinality constraints.
Make necessary assumptions in order to complete your schema and state those assumptions
along with the diagram.
You may use domain knowledge to complete information missing in the given specifications.
CSCC43 – Fall 2023 University of Toronto Scarborough
Question 1.2 [10 marks]:
Remove any generalizations (subclass), unnecessary data and structural redundancies,
multi-valued attributes, optional relationships, and irregularities from your model.
If you did modify your ER schema, show the improved version of ER Diagram in this stage.
By removing weak entity sets (if any), translate your ER diagram into Relational schema
following the PostgreSQL syntax.
Question 2 [15 marks]
We wish to carry out a reverse engineering operation. That is, given a relational database,
we wish to construct its conceptual representation using the E-R model. The database is for
an application concerning trains and railway stations and is made up of the following
relations:
o STATION (Code, Name, City) with a referential constraint between the attribute
City and the CITY relation;
o CITY (Code, Name, Region);
o ROUTE (From, To, Distance), with referential constraints between the attributes
From and the relation STATION and between the attribute To and the relation
STATION; this relation contains all and only the pairs of stations connected
directly by a route (that is without intermediate stations);
o TRAINTIMETABLE (Number, From, To, DepartureTime, ArrivalTime) with
referential constraints between the attributes From and the relation STATION
and between the attribute To, and the relation STATION;
o TRAINROUTE (TrainNumber, From, To) with referential constraints between the
attribute TrainNumber and the relation TRAINTIMETABLE and between the
attributes From and To and the relation STATION;
o STOPTIME (TrainNumber, Station, Arrival, Departure) with referential constraints
between the attribute TrainNumber and the relation TRAINTIMETABLE and
between the attribute Station and the relation STATION;
o ACTUALTRAIN (TrainNumber, Date, DepartureTime, ArrivalTime) with a
referential constraint between the attribute TrainNumber and the
TRAINTIMETABLE relation;
o ACTUALSTOP (TrainNumber, Date, Station, Arrival, Departure) with a referential
constraint between the two attributes TrainNumber and Station and the
STOPTIME relation.
Question 2.1 [15 marks]
For the above schema, construct its conceptual representation using the E-R model.
Recall that derived redundancy can be present in terms of attribute, entity, or relationship.
Find out any such derived redundancy in this model.
CSCC43 – Fall 2023 University of Toronto Scarborough
Part 2: Functional Dependencies and Normalization [60 marks]
Question 1 [5 marks]
Consider a relation S with six attributes A, B, C, D, E, and F. You are given the following
dependencies: AB → C, BC → D, D → E, CF → B.
a) What are all the non-trivial functional dependencies that follow from the given
functional dependencies? Make sure that the functional dependencies you list have
exactly one attribute on the right hand side.
b) What are all the candidate keys of S?
c) What are all the superkeys of S that are not candidate keys?
Question 2 [5 marks]
Consider a relation R with five attributes A, B, C, D, and E. You are given the following
dependencies: A → B, BC → E, and ED → A.
a) List all the candidate keys for R.
b) Is R in 3NF? Explain why or why not.
c) Is R in BCNF? Explain why or why not.
Question 3 [15 marks]
For all of the parts below, assume you are given a relation R with four attributes A, B, C, and
D. In each part you are also given a set of functional dependencies, assume those are the
only dependencies that hold for R and do the following:
(i) Identify the candidate key(s) for R.
(ii) Identify the best normal form that R satisfies (1NF, 2NF, 3NF, or BCNF).
(iii) If R is not in BCNF, give a lossless-join decomposition of R into BCNF.
a) C → D, C → A, B → C
b) B → C, D → A
c) AB → C, AB → D, C → A, D → B
CSCC43 – Fall 2023 University of Toronto Scarborough
Question 4 [15 marks]
In each part below you are given a relation with attributes as well as a set of functional
dependencies that hold for that relation. For each part, do the following:
(i) List all the candidate keys for the relation.
(ii) Give a lossless-join and dependency-preserving decomposition of the relation
into 3NF.
a) R(A, B, C, D, E); {A → BC, CD → E, B → D, E → A}
b) S(A, B, C, D, E, F); {C → A, CD → E, A → B, D → F}
c) T(A, B, C, D, E); { A → CD, B → CE, E → B}
Question 5 [10 marks]
 For each of the following relation schemas and dependencies do the following:
(i) Find all the 4NF violations.
(ii) Decompose the relations into a collection of relation schemas in 4NF.
a) R(A, B, C, D) with MVD's A àà B and B àà CD.
b) R(A, B, C, D, E) with MVD's A àà B and AB àà C and FD's A à D and AB à E.
Question 6 [10 marks]
Give counterexample relations to show why the following rules for MVD's do not hold. Hint:
apply the chase test and see what happens.
a) If A àà BC, then A àà B.
b) If A àà B, then A à B.
請加QQ:99515681 或郵箱:99515681@qq.com   WX:codehelp

掃一掃在手機打開當前頁
  • 上一篇:CS 2210編程代寫、Java程序語言代做
  • 下一篇:代寫ecs36c 有向圖程序
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    流體仿真外包多少錢_專業CFD分析代做_友商科技CAE仿真
    流體仿真外包多少錢_專業CFD分析代做_友商科
    CAE仿真分析代做公司 CFD流體仿真服務 管路流場仿真外包
    CAE仿真分析代做公司 CFD流體仿真服務 管路
    流體CFD仿真分析_代做咨詢服務_Fluent 仿真技術服務
    流體CFD仿真分析_代做咨詢服務_Fluent 仿真
    結構仿真分析服務_CAE代做咨詢外包_剛強度疲勞振動
    結構仿真分析服務_CAE代做咨詢外包_剛強度疲
    流體cfd仿真分析服務 7類仿真分析代做服務40個行業
    流體cfd仿真分析服務 7類仿真分析代做服務4
    超全面的拼多多電商運營技巧,多多開團助手,多多出評軟件徽y1698861
    超全面的拼多多電商運營技巧,多多開團助手
    CAE有限元仿真分析團隊,2026仿真代做咨詢服務平臺
    CAE有限元仿真分析團隊,2026仿真代做咨詢服
    釘釘簽到打卡位置修改神器,2026怎么修改定位在范圍內
    釘釘簽到打卡位置修改神器,2026怎么修改定
  • 短信驗證碼 寵物飼養 十大衛浴品牌排行 suno 豆包網頁版入口 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    国产人妻人伦精品_欧美一区二区三区图_亚洲欧洲久久_日韩美女av在线免费观看
    青青青免费在线| 亚洲人成无码www久久久| 国产精品视频内| 中国丰满熟妇xxxx性| 欧美亚洲伦理www| 久久另类ts人妖一区二区| 欧美激情一区二区三级高清视频 | 欧美日韩另类丝袜其他| 久久综合亚洲精品| 亚洲精品中文综合第一页| 成人久久精品视频| 欧美日韩福利电影| 加勒比海盗1在线观看免费国语版 加勒比在线一区二区三区观看 | 激情五月亚洲色图| 日韩综合中文字幕| 欧洲午夜精品久久久| 国产成人自拍视频在线观看| 亚洲第一综合| 久久综合九色欧美狠狠| 天堂精品视频| 国产成人精品日本亚洲| 日韩视频 中文字幕| 国产二区视频在线| 少妇久久久久久被弄到高潮| 国产精品678| 日韩啊v在线| 国产v亚洲v天堂无码久久久| 性高潮久久久久久久久| 91精品国产91久久久久青草| 亚洲视频欧美在线| 国产精品69页| 欧美在线一级视频| 久久综合免费视频| 成人免费91在线看| 日本一区二区在线播放| 国产成人精品自拍| 国内精品国产三级国产在线专| 国产精品视频一二三四区| 国产网站免费在线观看| 中文精品视频一区二区在线观看| 粉嫩av免费一区二区三区| 中文字幕一区二区三区四区五区六区| 99精品在线免费视频| 日韩中字在线观看| 久久精品这里热有精品| 麻豆成人在线播放| 亚洲中文字幕无码不卡电影 | 久久精品国产91精品亚洲 | 国产日韩精品电影| 亚洲欧美精品| 日韩在线观看精品| 免费久久99精品国产自| 欧美激情视频一区二区| 国产精品99蜜臀久久不卡二区| 日韩精品综合在线| 久久av在线看| 久久人人看视频| 欧美视频在线播放一区| 久久久久久国产精品| 久久亚洲国产精品日日av夜夜| 欧美一级大胆视频| 中文网丁香综合网| 日韩亚洲欧美中文在线| 国产美女直播视频一区| 色999五月色| 国产精品久久中文| 国产伦精品一区二区三区照片91| 欧美一区二区大胆人体摄影专业网站 | 不卡av电影在线观看| 99久久精品免费看国产一区二区三区 | 91九色在线视频| 欧美,日韩,国产在线| 亚洲精品一区二区三| 国产精品久久久久久亚洲影视| 91九色蝌蚪成人| 国产亚洲第一区| 日韩精品久久一区二区三区| 九九精品在线视频| 久久久国产一区| 久久久中文字幕| 国产三区二区一区久久| 欧美中文字幕视频| 亚州国产精品久久久| 久久综合色影院| 久久久成人精品视频| 国产精华一区| 国产精品一二三在线| 黄色一级片av| 日韩人妻无码精品久久久不卡| 自拍另类欧美| 久久在精品线影院精品国产| 日韩在线高清视频| 久久香蕉综合色| 99久久激情视频| 国产男女猛烈无遮挡91| 欧美综合在线观看| 欧美一区二区.| 亚洲二区三区四区| 亚洲淫片在线视频| 中文字幕精品在线播放| 久久综合网hezyo| 国产精品日韩一区二区三区| 久久久久久久久久久久av| 99在线免费视频观看| 国产精品中出一区二区三区| 国产在线观看不卡| 免费毛片一区二区三区久久久| 欧美在线观看一区二区三区| 肉大捧一出免费观看网站在线播放| 亚洲影院色在线观看免费| 欧美成人免费va影院高清| 国产精品久久久久久av福利软件 | www.av一区视频| 丰满人妻中伦妇伦精品app| 精品亚洲欧美日韩| 免费特级黄色片| 精品无码一区二区三区爱欲| 韩国精品久久久999| 欧美日韩一区在线观看视频| 茄子视频成人免费观看| 欧洲在线视频一区| 青青草原一区二区| 欧美亚洲免费在线| 欧美人与性禽动交精品| 欧美亚洲日本黄色| 黄色一级一级片| 国产一区二区三区小说| 国产日韩一区欧美| 国产乱子夫妻xx黑人xyx真爽| 国产免费xxx| 99精品一级欧美片免费播放| 91久久久久久久久| 国产成人精品视| 色偷偷av亚洲男人的天堂| 久久久精品亚洲| 国产精品久久久久久久久久尿 | 91久久偷偷做嫩草影院| 国产精品91久久久| 久久福利电影| 久久精品亚洲精品| 久久亚洲精品一区二区| 宅男av一区二区三区| 亚洲国产精品一区二区第四页av| 无码人妻精品一区二区蜜桃网站| 日本欧美中文字幕| 欧美久久综合性欧美| 国产午夜精品一区| 91精品久久久久久久久青青| 国产成人精品999| 国产精品三级网站| 色综合天天狠天天透天天伊人| 精品国产aⅴ麻豆| 亚洲国产一区二区在线| 日本精品一区二区| 蜜臀久久99精品久久久酒店新书| 国产欧美欧洲| 国产成人艳妇aa视频在线| 精品久久久91| 欧美精品第一页在线播放| 五月天色婷婷综合| 欧美日韩激情四射| 国产美女直播视频一区| 久久久久久www| 国产精品美女视频网站| 亚洲自偷自拍熟女另类| 青青在线免费观看视频| 国产在线青青草| 91精品一区二区| 国产精品手机视频| 亚洲国产精品女人| 欧美久久在线| 成人av在线亚洲| 久久久精品久久久久| 亚洲最新免费视频| 欧美连裤袜在线视频| 91免费视频网站在线观看| 久久久国产影院| 亚洲欧洲在线一区| 国内精品美女av在线播放| 国产精品99导航| 久久国产天堂福利天堂| 日韩一级免费看| 丰满少妇久久久| www欧美日韩| 亚洲精品无人区| 国产尤物99| xvideos亚洲| 手机看片福利永久国产日韩| 国产无套内射久久久国产| 久久久久久久激情| 亚洲欧洲精品在线观看| 精品无人区一区二区三区| 国产成人黄色av| 一区二区欧美日韩| 国产制服91一区二区三区制服| 国产富婆一区二区三区| 欧美激情视频给我| 黄色国产精品视频| 久久99国产精品99久久| 亚洲a中文字幕|