国产人妻人伦精品_欧美一区二区三区图_亚洲欧洲久久_日韩美女av在线免费观看

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

代寫SCC.363、代做Java,c++設計程序

時間:2024-02-11  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



202**024 ASSESSMENTS
Undergraduate
Individual Programming
Assessment Weighting [30%]
SCC.363 Security and Risk
Academic Honesty and Integrity
Students at Lancaster University are part of an academic community that values trust,
fairness and respect and actively encourages students to act with honesty and integrity. It is
a University policy that students take responsibility for their work and comply with the
university’s standards and requirements- found in the Manual of Academic Regulations and
Practice. By submitting their answers students will be confirming that the work submitted is
completely their own. By submitting their answers the group of students will be confirming
that the work submitted is that of the group. Academic misconduct regulations are in place
for all forms of assessment and students may familiarise themselves with this via the
university website:
https://www.lancaster.ac.uk/academic-standards-and-quality/regulations-policies-andcommittees/manual-of-academic-regulations-and-procedures/
Plagiarism
Plagiarism involves the unacknowledged use of someone else’s work and passing it off as if it
were one’s own. This covers every form of submitted work, from written essays, video
vignettes, and coding exercises. However, deliberately plagiarism with the intent to deceive
and gain academic benefit is unacceptable. This is a conscious, pre-meditated form of
cheating and is regarded as a serious breach of the core values of the University. More
information may be found via the plagiarism framework website. All coursework is to be
submitted electronically and will be run through our plagiarism detection mechanisms.
Please ensure you are familiar with the University's Plagiarism rules and if you are in any
doubt please contact your module tutor.
https://www.lancaster.ac.uk/academic-standards-and-quality/regulations-policies-andcommittees/principles-policies-and-guidelines/plagiarism-framework/
General Guidance:
This is an individual assessment that will count for 30% of your overall mark for this module.
Learning objectives
• Develop appreciation and understanding of security concepts.
• Formulate troubleshooting methods to identify/solve problems.
• Evaluate information to argue solution choices critically.
• Effectively communicate ideas.
Submission requirements
Prepare and submit your coding solutions on Coderunner. For all coding solutions, you must
use Python3. You can use modules from standard Python3 and cryptography.io. Your code
should include appropriate comments explaining what you do and why. All implementations
must be in Python3, and the cryptography.io library must be used for any cryptographyrelated functions (if needed). If you must consider padding in any task, you should use PKCS7.
Your code should include appropriate comments explaining your solution.
Example of the type of comments you SHOULD AVOID -- the comments don't explain the
solution:
def avalancheCalculator(string1, string2):
 # I hash the strings and generate the hexdigest values
 hexstring1 = hashlib.sha256(string1.encode()).hexdigest()
 hexstring2 = hashlib.sha256(string2.encode()).hexdigest()

 # I convert the hexdigest to integers
 int1 = int(hexstring1, 16)
 int2 = int(hexstring2, 16)
 # I XOR the integers
 intResult = int1 ^ int2

 # I return the 1's in the binary representation.
 return ( bin(intResult).count('1') )
Examples of types of comments that provide adequate information – the comments explain
the solution to the problem:
def avalancheCalculator(string1, string2):
 # A solution to the problem is to xor the integer representation
 # of the two values and count in the resulting int the number of bits
 # having the value of 1.
 hexstring1 = hashlib.sha256(string1.encode()).hexdigest()
 hexstring2 = hashlib.sha256(string2.encode()).hexdigest()

 int1 = int(hexstring1, 16)
 int2 = int(hexstring2, 16)
 intResult = int1 ^ int2

 # The "1"s in the binary representation of the XOR operation
 # represent which bits from int1 and int2 are different.
 # This is due to applying the XOR operation. 0^1 = 1, 1^0 = 1
 # Counting the "1"s will provide how many bits differ
 return ( bin(intResult).count('1') )
You have to upload the implementation of your functions on CodeRunner.
Marking Guidelines:
• You have to answer all three (3) tasks. Marks will be allocated based on the clarity of your
solution, comments in the code, and correctness. More information is provided within the
individual questions.
• The name of functions, type/number of variables, and return values must follow the tasks’
guidelines. Failing to adhere to this may result in not receiving marks.
Deadline for submissions: Friday 16
th February 16:00
TASK 1
--------
You are provided with the ds_hash hash function. The function receives a
finite message as input and produces a non-negative integer, which we
consider to be the hash value of the given message.
The size of input messages is fixed and always equals 64 bytes. Implement an
appropriate attack to check if the hash function ds_hash is strong collision
resistant. Your alphabet should include all lower-case and upper-case letters
of the English alphabet and all numbers from 0 to 9.
# -- START OF YOUR CODERUNNER SUBMISSION CODE
# INCLUDE ALL YOUR IMPORTS HERE
def ds_hash(message: str) -> int:
 hash_value = 0
 for ch in message:
 hash_value = (hash_value * 71) + ord(ch)

 return hash_value & 0x7FFFFFFF
def myAttack() -> bool:
# YOUR IMPLEMENTATION
return # True or False
# -- END OF YOUR CODERUNNER SUBMISSION CODE
#You can test your code in your system (NOT IN YOUR CODERUNNER SUBMISSION)
as follows:
# MAIN
if __name__ == "__main__":
print( myAttack() )
Marking scheme: This task's weight is 35% for providing a valid attack and
commenting on your code.
TASK 2
--------
Implement an HMAC based on the RFC-2104 definition (Section 2). The RFC is
available at the following link: https://www.rfc-editor.org/rfc/rfc2104
Below is the extract from the RFC that describes how the HMAC can be
implemented, and this is what you need to implement. The text is amended to
provide specific information about the selected H cryptographic hash
function, i.e., SHA256.
 The definition of HMAC requires a cryptographic hash function, which
 we denote by H, and a secret key K. In your implementation, assume H
 to be the SHA256 cryptographic hash function.
 We denote by B the byte-length of such blocks (B=64 for SHA256),
 and by L the byte-length of hash outputs (L=** for SHA256).
 The authentication key K can be of any length up to B, the
 block length of the hash function. Applications that use keys longer
 than B bytes will first hash the key using H and then use the
 resultant L byte string as the actual key to HMAC. In any case the
 minimal recommended length for K is L bytes (as the hash output
 length).
 We define two fixed and different strings ipad and opad as follows
 (the 'i' and 'o' are mnemonics for inner and outer):
 ipad = the byte 0x36 repeated B times
opad = the byte 0x5C repeated B times.
 To compute HMAC over the data `text' we perform
 H(K XOR opad, H(K XOR ipad, text))
 Namely,
 (1) append zeros to the end of K to create a B byte string
 (e.g., if K is of length 20 bytes and B=64, then K will be
 appended with 44 zero bytes 0x00)
 (2) XOR (bitwise exclusive-OR) the B byte string computed in step
 (1) with ipad
 (3) append the stream of data 'text' to the B byte string resulting
 from step (2)
 (4) apply H to the stream generated in step (3)
 (5) XOR (bitwise exclusive-OR) the B byte string computed in
 step (1) with opad
 (6) append the H result from step (4) to the B byte string
 resulting from step (5)
 (7) apply H to the stream generated in step (6) and output
 the result
The function's name has to be CustomHMAC and defined as follows.
# -- START OF YOUR CODERUNNER SUBMISSION CODE
# INCLUDE ALL YOUR IMPORTS HERE
def CustomHMAC(key: bytes, text: str) -> str:
# YOUR IMPLEMENTATION
return # YOUR RESULT
# -- END OF YOUR CODERUNNER SUBMISSION CODE
#You can test your code in your system (NOT IN YOUR CODERUNNER SUBMISSION)
as follows:
# MAIN
if __name__ == "__main__":
 k = os.urandom(16) # k is <class 'bytes'>
 txt = "hello world!!!!" # txt is <class 'str'>

 print( CustomHMAC(k, txt) )
 # The output will be a string of hexadecimal values, e.g.: a51b … 35fa

You can debug your code against the result from the following function:
from cryptography.hazmat.primitives import hashes, hmac
def HMAC_from_Cryptography(key: bytes, text: str) -> str:
 h = hmac.HMAC(key, hashes.SHA256())
 h.update(text.encode())
 signature = h.finalize().hex()

 return signature
Marking scheme: This task's weight is 40%, which will be allocated equally
for correctly implementing the steps and commenting on your code.
TASK 3
--------
Using the AES-ECB encryptor from the cryptography.io module, implement the
AES mode in Figure 1. You can instantiate an AES-ECB encryptor as follows:
from cryptography.hazmat.primitives.ciphers import Cipher, algorithms,
modes
key = # SELECT AN APPROPRIATE KEY FOR AES
cipher = Cipher(algorithms.AES(key), modes.ECB())
encryptor = cipher.encryptor()
Figure 1 - The figure describes a mode of AES for encrypting plaintext to ciphertext
The function's name has to be CustomAESmode and defined as follows:
# -- START OF YOUR CODERUNNER SUBMISSION CODE
# INCLUDE ALL YOUR IMPORTS HERE
def CustomAESMode(key: bytes, iv: bytes, plaintext: str) -> str:
# YOUR IMPLEMENTATION
return # THE CIPHERTEXT
# -- END OF YOUR CODERUNNER SUBMISSION CODE
#You can test your code in your system (NOT IN YOUR CODERUNNER SUBMISSION)
as follows:
# MAIN
if __name__ == "__main__":
 key = bytes.fromhex("06a9214036b8a15b512e03d534120006")
 iv = bytes.fromhex("3dafba429d9eb430b422da802c9fac41")
 txt = "This is a text"

 print( CustomAESMode(key, iv, txt) )
 # The result using the above input should be:
1827bfc04f1a455eb101b943c44afc1d
Marking scheme: This task's weight is 25%, which will be allocated equally
for correctly implementing the steps and commenting on your code.
如有需要,請加QQ:99515681 或WX:codehelp

掃一掃在手機打開當前頁
  • 上一篇:代做CA3 Group程序、Java編程設計代寫
  • 下一篇:CS170程序代做、Python編程設計代寫
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    流體仿真外包多少錢_專業CFD分析代做_友商科技CAE仿真
    流體仿真外包多少錢_專業CFD分析代做_友商科
    CAE仿真分析代做公司 CFD流體仿真服務 管路流場仿真外包
    CAE仿真分析代做公司 CFD流體仿真服務 管路
    流體CFD仿真分析_代做咨詢服務_Fluent 仿真技術服務
    流體CFD仿真分析_代做咨詢服務_Fluent 仿真
    結構仿真分析服務_CAE代做咨詢外包_剛強度疲勞振動
    結構仿真分析服務_CAE代做咨詢外包_剛強度疲
    流體cfd仿真分析服務 7類仿真分析代做服務40個行業
    流體cfd仿真分析服務 7類仿真分析代做服務4
    超全面的拼多多電商運營技巧,多多開團助手,多多出評軟件徽y1698861
    超全面的拼多多電商運營技巧,多多開團助手
    CAE有限元仿真分析團隊,2026仿真代做咨詢服務平臺
    CAE有限元仿真分析團隊,2026仿真代做咨詢服
    釘釘簽到打卡位置修改神器,2026怎么修改定位在范圍內
    釘釘簽到打卡位置修改神器,2026怎么修改定
  • 短信驗證碼 寵物飼養 十大衛浴品牌排行 suno 豆包網頁版入口 wps 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    国产人妻人伦精品_欧美一区二区三区图_亚洲欧洲久久_日韩美女av在线免费观看
    久久久久久久久久久久久久国产| 国产一区二区高清不卡| 欧美在线不卡区| 91好吊色国产欧美日韩在线| 综合一区中文字幕| 国产噜噜噜噜久久久久久久久| 国产精品-区区久久久狼| 日韩午夜视频在线观看| 久久免费国产精品1| 亚洲中文字幕无码一区二区三区| 国产欧美一区二区三区久久人妖| 国产精品福利网站| 国产自产在线视频| 久久综合国产精品台湾中文娱乐网| 欧美区高清在线| 国产传媒久久久| 日本不卡二区| 久久久精品免费| 精品人妻人人做人人爽| 国产精品久久久久久久久久久不卡| 黄色特一级视频| 久久躁狠狠躁夜夜爽| 精品一区二区日本| 国产精品裸体瑜伽视频| 狠狠久久综合婷婷不卡| 国产精品日韩欧美综合| 国内免费久久久久久久久久久| 国产精品久久久对白| 黄色一级二级三级| 国产精品久久在线观看| 国内精品一区二区| 久久国产精品久久久久久久久久| 国产精品一区二区在线观看| 一级一片免费播放| 91久久嫩草影院一区二区| 色播亚洲视频在线观看| 久久久久久中文| 欧美久久久久久| 美女久久久久久久久久久| 成人做爽爽免费视频| 色一情一乱一伦一区二区三区丨| 色阁综合伊人av| 国产一区二区三区四区五区加勒比 | 久久久久久久久久久99| 欧美二区在线| 久久久久国产精品免费| 久久久久九九九| 黄色网在线视频| 亚洲午夜高清视频| www.欧美三级电影.com| 国产性生活免费视频| 亚洲第一综合网站| 久久超碰亚洲| 精品少妇人妻av免费久久洗澡| 欧美激情第1页| 久久久一本精品99久久精品66| 日本精品一区二区三区不卡无字幕| 久久久国产在线视频| 国产欧美精品久久久| 日本一区高清在线视频| 国产精品网红福利| 91免费看片在线| 激情视频小说图片| 亚洲AV无码成人精品一区| 国产精品区二区三区日本| 99精品国产一区二区| 欧美不卡福利| 亚洲一区精彩视频| 国产精品视频免费观看www| 成人av一级片| 欧美在线视频a| 亚洲一区免费看| 国产精品久久国产三级国电话系列| 不卡中文字幕在线| 欧美凹凸一区二区三区视频| 无码人妻精品一区二区蜜桃百度| 久久亚洲一区二区三区四区五区高| 久久综合久久久| 国产日产久久高清欧美一区| 日韩欧美一区二区视频在线播放| 久久久久成人精品| 久久精品亚洲一区| 成人福利网站在线观看11| 激情五月综合色婷婷一区二区| 天堂精品一区二区三区| 久久91精品国产91久久跳| 日韩在线视频一区| 91蜜桃网站免费观看| 国产网站免费在线观看| 欧美日韩精品综合| 日本久久久久久久久久久| 亚洲在线一区二区| 精品国产一区二区三区在线| 国产精品视频免费一区| 久草热视频在线观看| 97精品视频在线| 国产伦精品一区二区三区 | 国产精品久久久久久av福利| 久久精品国产第一区二区三区最新章节| 国产日韩欧美综合精品| 黄页网站在线观看视频| 欧美亚洲视频在线观看| 日本新janpanese乱熟| 亚洲一区在线免费| 久久久久久com| 欧美激情视频三区| 欧美激情第三页| 精品国产乱码久久久久久88av | 国产精品一区二区三区精品| 麻豆成人av| 精品午夜一区二区| 蜜桃在线一区二区三区精品| 欧美激情一区二区三区在线视频| 人人澡人人澡人人看欧美| 日本久久久a级免费| 日韩av大片免费看| 性高潮久久久久久久久| 亚洲一区二区三区sesese| 亚洲综合在线小说| 亚洲图片都市激情| 亚洲欧洲久久| 亚洲第一综合网站| 日韩av免费在线看| 日韩在线一级片| 日本精品视频在线| 欧美有码在线视频| 欧美xxxx黑人又粗又长精品| 精品一区二区不卡| 国产日产久久高清欧美一区| 不卡视频一区| 国产盗摄视频在线观看| 日韩在线资源网| 国产精品免费网站| 伦理中文字幕亚洲| 中国人体摄影一区二区三区| 亚洲综合中文字幕在线| 亚洲mm色国产网站| 日本a级片在线观看| 日韩免费高清在线观看| 欧美精品123| 国产一区二区不卡视频在线观看| 国产欧亚日韩视频| 99视频在线免费观看| 久久精品国产综合精品| 国产精品免费久久久久影院| 久操成人在线视频| 亚洲a级在线观看| 欧美亚洲国产日本| 国产欧美在线一区| 久久久免费看| 国产精品女主播视频| 亚洲午夜高清视频| 奇米成人av国产一区二区三区| 欧美亚洲视频一区| 国产伦精品一区二区三区视频孕妇| 91精品国产综合久久香蕉最新版 | 国产欧美一区二区三区久久 | 日日骚av一区| 欧美激情视频三区| 午夜精品久久久久久久男人的天堂| 日韩人妻一区二区三区蜜桃视频| 加勒比在线一区二区三区观看| 国产免费毛卡片| 久久免费在线观看| 视频在线一区二区| 九九久久国产精品| 日本在线观看a| 国产一区二区三区高清| 国产高清不卡无码视频| 国产精品二区三区| 色中色综合成人| 国产中文字幕亚洲| 久久久久狠狠高潮亚洲精品| 国产精品高清在线| 日本一区二区视频| 国产欧美韩日| www.亚洲免费视频| 在线观看一区二区三区三州| 品久久久久久久久久96高清| 激情五月五月婷婷| 久久综合九色综合久99| 久久成人综合视频| 日韩美女免费线视频| 国产精品自在线| 国产精品无码一区二区在线| 亚洲欧洲国产精品久久| 麻豆成人av| 久久精品人成| 亚洲一区二区三区sesese| 免费黄色福利视频| 久久久久久久久久久久久久久久久久av| 欧美激情亚洲自拍| 狠狠精品干练久久久无码中文字幕 | 国产视频九色蝌蚪| 色av吧综合网| 电影午夜精品一区二区三区 | 91久久国产综合久久91精品网站| 国产精品日韩一区二区免费视频 | 日本成人精品在线| 国产女大学生av|